Write an equation in point-slope form of the line having the given slope that contains the given point. m= 3 4 m=34 , (36,24)

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Write an equation in point-slope form of the line having the given slope that contains the given point. m= 3 4 m=34 , (36,24)

[tex]\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})~\hspace{10em} \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-3}[x-\stackrel{x_1}{(-2)}]\implies y-1=-3(x+2)[/tex]

b. [tex](y-12.8)=-0.8(x-14.5)[/tex]

Step-by-step explanation:

We know that the equation of a line in point slope form with slope m and passing through point (a,b) is given by :-

[tex](y-b)=m(x-a)[/tex]

Given : The slope of the line : m= -0.8

The point from which line is passing : (a,b) =(14.5,12.8)

Then , the equation in point slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) :-

[tex](y-12.8)=-0.8(x-14.5)[/tex]

c

Step-by-step explanation:

It would be c because you would add subtract 30 - x which equals 30x then you would divided 5 / 6 which equals 0.12 then you would add y plus some number which equals 12y then you would add 12y+12=24y=24y / 2=12 thenyou have 30x,12y.

All we have to do is input the x, y, and m value into the equation. It'd look like tihs:

y - 24 = 34(x -36)

Hello :

an equation in point-slope form is : y -3 = 5 (x-4)

A

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 3 and (a, b) = (- 2, 1), thus

y - 1 = - 3(x - (- 2)), that is

y - 1 = - 3(x + 2) → A

The following equation can be written with the formula for point slope.

y-y1=m(x-x1)

m= slope or rise/run

y1 and x1= x and y coordinates of a point.

point=(x,y)

We substitute the values in and get the following equation.

y-5=4(x-2)

Which is our final answer.

Hope this helps!

D

Step-by-step explanation:

A might be right for the wrong linear equation type. It could be describing a y intercept slope line. So even if it is right, it is not the answer. Actually the answer to A should be y = (5/6)x - 13

The general formula for the answer you want is

Givens

y -y1 = m(x - x1)

x1 = 30

y1 = 12

m = 5/6

Solution

y - 12 = (5/6)(x - 30)

That makes the answer D

Point-slope form is [tex]y-y_1=m(x-x_1)[/tex], where the point [tex]P(x_1,y_1)[/tex] lies on the graph and m is the slope of the graph.

We have a point (30, 12) and a slope of 56.

So we write [tex]y-12=56(x-30)[/tex]. And we're done.

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 36}}\quad ,&{{ 24}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 34 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \begin{array}{llll} \textit{plug in the values for } \begin{cases} y_1=24\\ x_1=36\\ m=34 \end{cases}\\ \end{array}\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form}[/tex]