Write an equation of the line that is perpendicular toY=-7/4x+8 and contains (-7,2) Posted on October 23, 2021 By Lex1kkkk 4 Comments on Write an equation of the line that is perpendicular toY=-7/4x+8 and contains (-7,2) Write an equation of the line that is perpendicular to Y=-7/4x+8 and contains (-7,2) Mathematics
see attachedstep-by-step explanation:given the function as;[tex]f(x)=2x^3-7x^2+2x+3[/tex]write the equation replacing f(x) with y[tex]y=2x^3-7x^2+2x+3[/tex]form and fill a table containing values of y with corresponding values of xyou can take a range for values of x as -3≤x≤3 solving for x=-3 [tex]f(-3)=2*-3^3-7*-3^2+2*-3+3=2*-27-63+-6+3=-54-63-6+3y=-120[/tex]for x=-2[tex]f(-2)=2*-2^3-7*-2^2+2*-2+3=2*-8-28+-4+3=-16-28-4+3=-45[/tex]repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3plot the values of y against values of x and obtain the following graphReply
sorry man i accidentally pressed yes my bad
step-by-step explanation:
see attached
step-by-step explanation:
given the function as;
[tex]f(x)=2x^3-7x^2+2x+3[/tex]
write the equation replacing f(x) with y
[tex]y=2x^3-7x^2+2x+3[/tex]
form and fill a table containing values of y with corresponding values of x
you can take a range for values of x as -3≤x≤3
solving for x=-3
[tex]f(-3)=2*-3^3-7*-3^2+2*-3+3=2*-27-63+-6+3=-54-63-6+3y=-120[/tex]
for x=-2
[tex]f(-2)=2*-2^3-7*-2^2+2*-2+3=2*-8-28+-4+3=-16-28-4+3=-45[/tex]
repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3
plot the values of y against values of x and obtain the following graph
what is the question?
step-by-step explanation:
Is there a picture of a graph or whatever that goes along with this?