Write an equation of the line with the given information. use slope-intercept form or point slope form. the final answer must be in slope intercept form y=mx+b. show work

[tex]Write an equation of the line with the given information. use slope-intercept form or point slope fo[/tex]

Y=mx+b, where m is the slope and b is the y-intercept.

m=(y2-y1)/(x2-x1)=(4-8)/(-3-3)-4/-6=2/3 so

y=2x/3 + b, using either point, we can solve for the y-intercept...using (3,8)

8=2(3)/3 + b

8=2+b

b=6 so the line is:

y=2x/3 + 6 or more neatly

y=(2x+18)/3

Slope = (6 +9) / (2 +1) = 15/3 = 5

y = mx + b

-9 = 5(-1) +b

b = - 4

equation

y = 5x - 4

Y = m x + b

m : slope

b :intercept

m = -9 - 27/ 2 +2 = -9

y = -9 x + b

27 = -18 +b

b = 45

y = -9 x + 45

y = 6

Step-by-step explanation:

Find the y intercept (b) by plugging in (x,y) and m into y = mx + b

6 = 0 (-2) + b

6 = b

The equation will be y = 0x + 6 OR y = 6

Slope = (2 -10) / (3 +1) = -8/4 = -2

y = mx + b

10 = -2 (-1) +b

b = 8

equation

y = -2x + 8

Slope = (-9 -27)/(2 +2) = -36/4 = -9

y = mx + b

27 = -9(-2) + b

27 = 18 + b

b = 9

equation

y = -9x +9

The equation of the line is y=2/3x+6

9. [tex]y=3x-3[/tex]

10. [tex]y=8x+b[/tex]

Step-by-step explanation:

For question 9.

The given information is [tex]m=3, b=-3[/tex]

The equation of a line is written as.

[tex]y=mx+b[/tex]-----------(1)

Where m is the slope of the line and b is the y intercept.

Put the m and b value in equation 1.

[tex]y=3x-3[/tex]

So, the equation of the line is [tex]y=3x-3[/tex]

For question 10.

Given:

[tex]m = 8[/tex]

The equation of a line is written as.

[tex]y=mx+b[/tex]-----------(1)

Where m is the slope of the line and b is the y intercept.

Put the m value in equation 1.

[tex]y=8x+b[/tex]

So, the equation of the line is [tex]y=8x+b[/tex].