Write an equation of the line with the given information. use slope-intercept form or point slope form. the final answer must be in slope intercept form y=mx+b. show work
[tex]Write an equation of the line with the given information. use slope-intercept form or point slope fo[/tex]
Y=mx+b, where m is the slope and b is the y-intercept.
m=(y2-y1)/(x2-x1)=(4-8)/(-3-3)-4/-6=2/3 so
y=2x/3 + b, using either point, we can solve for the y-intercept...using (3,8)
8=2(3)/3 + b
8=2+b
b=6 so the line is:
y=2x/3 + 6 or more neatly
y=(2x+18)/3
Slope = (6 +9) / (2 +1) = 15/3 = 5
y = mx + b
-9 = 5(-1) +b
b = - 4
equation
y = 5x - 4
Y = m x + b
m : slope
b :intercept
m = -9 - 27/ 2 +2 = -9
y = -9 x + b
27 = -18 +b
b = 45
y = -9 x + 45
y = 6
Step-by-step explanation:
Find the y intercept (b) by plugging in (x,y) and m into y = mx + b
6 = 0 (-2) + b
6 = b
The equation will be y = 0x + 6 OR y = 6
Slope = (2 -10) / (3 +1) = -8/4 = -2
y = mx + b
10 = -2 (-1) +b
b = 8
equation
y = -2x + 8
Slope = (-9 -27)/(2 +2) = -36/4 = -9
y = mx + b
27 = -9(-2) + b
27 = 18 + b
b = 9
equation
y = -9x +9
The equation of the line is y=2/3x+6
9. [tex]y=3x-3[/tex]
10. [tex]y=8x+b[/tex]
Step-by-step explanation:
For question 9.
The given information is [tex]m=3, b=-3[/tex]
The equation of a line is written as.
[tex]y=mx+b[/tex]-----------(1)
Where m is the slope of the line and b is the y intercept.
Put the m and b value in equation 1.
[tex]y=3x-3[/tex]
So, the equation of the line is [tex]y=3x-3[/tex]
For question 10.
Given:
[tex]m = 8[/tex]
The equation of a line is written as.
[tex]y=mx+b[/tex]-----------(1)
Where m is the slope of the line and b is the y intercept.
Put the m value in equation 1.
[tex]y=8x+b[/tex]
So, the equation of the line is [tex]y=8x+b[/tex].