Write and solve an equation to determine the base of a parallelogram whose area is 105 meters^2 and whose height is 7 meters. Choices
A: b = 30 meters
B: b = 15 meters
C: b = 735 meters
D: b = 91 meters
(Please help me...)
Write and solve an equation to determine the base of a parallelogram whose area is 105 meters^2 and whose height is 7 meters. Choices
A: b = 30 meters
B: b = 15 meters
C: b = 735 meters
D: b = 91 meters
(Please help me...)
Area = (base)*(height)
15 = (x+7)(x-7)
(x+7)(x-7) = 15
x^2 - 49 = 15
x^2 - 49+49 = 15+49
x^2 = 64
sqrt(x^2) = sqrt(64)
x = 8 ... note that x can't be negative
If x = 8, then the base is...
x+7 = 8+7 = 15
Therefore the base is 15 units.
(the height is x-7 = 8-7 = 1 unit)
correct
Step-by-step explanation:
he will have 300 because he is really broke and 300 is in his imangine
step-by-step explanation: he ehe heh step by the thy
Area = length of base × altitude
34 = 8.5 × a
34 = 8.5a
a = 34/8.5
a = 4
The altitude of the corresponding side is 4 cm
The height of parallelogram is [tex]2x^2-7x+1[/tex]
Step-by-step explanation:
Area of parallelogram =[tex]Base \times Height[/tex]
Area of parallelogram = [tex]2x^3 -x^2 -20x + 3[/tex]
Base of parallelogram = x+3
So, [tex]2x^3-x^2-20x + 3 = height \times (x+3)[/tex]
[tex]\frac{2x^3- x^2 -20x + 3}{x+3}= height\\2x^2-7x+1=Height[/tex]
Hence The height of parallelogram is [tex]2x^2-7x+1[/tex]
Did u want to find the value of x?