Write and solve an equation to determine the base of a parallelogram whose area is 105 meters^2 and whose height is 7 meters. Choices

A: b = 30 meters

B: b = 15 meters

C: b = 735 meters

D: b = 91 meters

(Please help me...)

Skip to content# Write and solve an equation to determine the base of a parallelogram whose area is 105 meters^2 and whose height is 7 meters.Choices A: b = 30 metersB:

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Write and solve an equation to determine the base of a parallelogram whose area is 105 meters^2 and whose height is 7 meters. Choices

A: b = 30 meters

B: b = 15 meters

C: b = 735 meters

D: b = 91 meters

(Please help me...)

Area = (base)*(height)

15 = (x+7)(x-7)

(x+7)(x-7) = 15

x^2 - 49 = 15

x^2 - 49+49 = 15+49

x^2 = 64

sqrt(x^2) = sqrt(64)

x = 8 ... note that x can't be negative

If x = 8, then the base is...

x+7 = 8+7 = 15

Therefore the base is 15 units.

(the height is x-7 = 8-7 = 1 unit)

correct

Step-by-step explanation:

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

Area = length of base × altitude

34 = 8.5 × a

34 = 8.5a

a = 34/8.5

a = 4

The altitude of the corresponding side is 4 cm

The height of parallelogram is [tex]2x^2-7x+1[/tex]

Step-by-step explanation:

Area of parallelogram =[tex]Base \times Height[/tex]

Area of parallelogram = [tex]2x^3 -x^2 -20x + 3[/tex]

Base of parallelogram = x+3

So, [tex]2x^3-x^2-20x + 3 = height \times (x+3)[/tex]

[tex]\frac{2x^3- x^2 -20x + 3}{x+3}= height\\2x^2-7x+1=Height[/tex]

Hence The height of parallelogram is [tex]2x^2-7x+1[/tex]

Did u want to find the value of x?