Write the series using summation notation -2 + 4+ -8 + 16 + -32​

Write the series using summation notation -2 + 4+ -8 + 16 + -32​

Related Posts

This Post Has 10 Comments

  1. The formula is
    [tex]\frac{a_1(1-r^n)}{1-r}[/tex]
    a1=first term
    n=which term
    r=common ratio
    we see the common ratio is -2
    frs term is 1
    and we go to 10th term so n=10

    [tex]\frac{1(1-(-2)^{10})}{1-(-2)}[/tex]
    [tex]\frac{1(1-1024)}{1+2}[/tex]
    [tex]\frac{1(-1023)}{3}[/tex]
    -341
    the sum is -341

  2. It's b. -1,-2,-4,-8,-16,-32
    because 
    [tex]a_n=2a_{n-1} \mbox{ where } a_1=-1.\\
So\\
a_2=2a_1=-2\\
a_3=2a_2=-4\\
a_4=2a_3=-8\\
a_5=2a_4=-16\\
a_6=2a_5=-32.[/tex]

  3. you multiply it by -2 each time

    Explanation:

    positive times negative = negative

    negative times negative= positive  

  4. Remark

    You can find the answer to that by dividing any 2 consecutive terms putting the right one in the numerator and the left one in the denominator.

    Forumula

    ratio = right/left

    right = - 8

    left = 4

    ratio = -8/4

    ratio = -2

    Any two numbers would work.

    ratio = - 32/16 = - 2

  5. Hello,

    [tex]u_{1}= -2 \\
u_{2}= -2 *(-2)=(-2)^2 \\
u_{3}= (-2)^2 *(-2)=(-2)^3 \\
u_{4}= (-2)^3 *(-2)=(-2)^4 \\

...\\

\boxed{u_{n}= (-2)^n} \\

[/tex]

Leave a Reply

Your email address will not be published. Required fields are marked *